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Enumerable.Last<TSource> Method (IEnumerable<TSource>)

Returns the last element of a sequence.

Namespace:  System.Linq
Assemblies:   System.Linq (in System.Linq.dll)
  System.Core (in System.Core.dll)

public static TSource Last<TSource>(
	this IEnumerable<TSource> source
)

Type Parameters

TSource

The type of the elements of source.

Parameters

source
Type: System.Collections.Generic.IEnumerable<TSource>

An IEnumerable<T> to return the last element of.

Return Value

Type: TSource
The value at the last position in the source sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<TSource>. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

ExceptionCondition
ArgumentNullException

source is null.

InvalidOperationException

The source sequence is empty.

The Last<TSource>(IEnumerable<TSource>) method throws an exception if source contains no elements. To instead return a default value when the source sequence is empty, use the LastOrDefault method.

The following code example demonstrates how to use Last<TSource>(IEnumerable<TSource>) to return the last element of an array.

            int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54, 
                                83, 23, 87, 67, 12, 19 };

            int last = numbers.Last();

            Console.WriteLine(last);

            /*
             This code produces the following output:

             19
            */

.NET Framework

Supported in: 4.6, 4.5, 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

XNA Framework

Supported in: 3.0

Portable Class Library

Supported in: Portable Class Library

Supported in: Windows Phone 8.1

Supported in: Windows Phone Silverlight 8.1

Supported in: Windows Phone Silverlight 8
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