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Enumerable::Min<TSource> Method (IEnumerable<TSource>)

Returns the minimum value in a generic sequence.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

[ExtensionAttribute]
public:
generic<typename TSource>
static TSource Min(
	IEnumerable<TSource>^ source
)

Type Parameters

TSource

The type of the elements of source.

Parameters

source
Type: System.Collections.Generic::IEnumerable<TSource>

A sequence of values to determine the minimum value of.

Return Value

Type: TSource
The minimum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<TSource>. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

ExceptionCondition
ArgumentNullException

source is nullptr.

If type TSource implements IComparable<T>, this method uses that implementation to compare values. Otherwise, if type TSource implements IComparable, that implementation is used to compare values.

If TSource is a reference type and the source sequence is empty or contains only values that are nullptr, this function returns nullptr.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

The following code example demonstrates how to use Min<TSource>(IEnumerable<TSource>) to determine the minimum value in a sequence of IComparable<T> objects.

No code example is currently available or this language may not be supported.

.NET Framework

Supported in: 4.6, 4.5, 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

XNA Framework

Supported in: 3.0

Portable Class Library

Supported in: Portable Class Library

Supported in: Windows Phone 8.1

Supported in: Windows Phone Silverlight 8.1

Supported in: Windows Phone Silverlight 8
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