Queryable.Intersect(Of TSource) Method (IQueryable(Of TSource), IEnumerable(Of TSource))
Produces the set intersection of two sequences by using the default equality comparer to compare values.
Assembly: System.Core (in System.Core.dll)
<ExtensionAttribute> Public Shared Function Intersect(Of TSource) ( source1 As IQueryable(Of TSource), source2 As IEnumerable(Of TSource) ) As IQueryable(Of TSource)
Parameters
- source1
-
Type:
System.Linq.IQueryable(Of TSource)
A sequence whose distinct elements that also appear in source2 are returned.
- source2
-
Type:
System.Collections.Generic.IEnumerable(Of TSource)
A sequence whose distinct elements that also appear in the first sequence are returned.
Return Value
Type: System.Linq.IQueryable(Of TSource)A sequence that contains the set intersection of the two sequences.
Type Parameters
- TSource
The type of the elements of the input sequences.
| Exception | Condition |
|---|---|
| ArgumentNullException | source1 or source2 is null. |
The Intersect(Of TSource)(IQueryable(Of TSource), IEnumerable(Of TSource)) method generates a MethodCallExpression that represents calling Intersect(Of TSource)(IQueryable(Of TSource), IEnumerable(Of TSource)) itself as a constructed generic method. It then passes the MethodCallExpression to the CreateQuery(Of TElement)(Expression) method of the IQueryProvider represented by the Provider property of the source1 parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Intersect(Of TSource)(IQueryable(Of TSource), IEnumerable(Of TSource)) depends on the implementation of the type of the source1 parameter. The expected behavior is that all the elements in source1 that are also in source2 are returned.
The following code example demonstrates how to use Intersect(Of TSource)(IQueryable(Of TSource), IEnumerable(Of TSource)) to return the elements that appear in each of two sequences.
Dim id1() As Integer = {44, 26, 92, 30, 71, 38} Dim id2() As Integer = {39, 59, 83, 47, 26, 4, 30} ' Get the numbers that occur in both arrays (id1 and id2). Dim both As IEnumerable(Of Integer) = id1.AsQueryable().Intersect(id2) Dim output As New System.Text.StringBuilder For Each id As Integer In both output.AppendLine(id) Next ' Display the output. MsgBox(output.ToString()) ' This code produces the following output: ' 26 ' 30
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.1
Windows Phone
Available since 8.1