Enumerable.Max Method (IEnumerable<Int64>)

 

Returns the maximum value in a sequence of Int64 values.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static long Max(
	this IEnumerable<long> source
)

Parameters

source
Type: System.Collections.Generic.IEnumerable<Int64>

A sequence of Int64 values to determine the maximum value of.

Return Value

Type: System.Int64

The maximum value in the sequence.

Exception Condition
ArgumentNullException

source is null.

InvalidOperationException

source contains no elements.

The Max(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

Universal Windows Platform
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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