ContainerControl::IContainerControl::ActivateControl Method (Control^)


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Activates the specified control.

Namespace:   System.Windows.Forms
Assembly:  System.Windows.Forms (in System.Windows.Forms.dll)

virtual bool ActivateControl(
	Control^ control
) sealed = IContainerControl::ActivateControl


Type: System.Windows.Forms::Control^

The Control to activate.

Return Value

Type: System::Boolean

true if the control is successfully activated; otherwise, false.

The control parameter must be a child of the container control.

The following code example demonstrates how to inherit from the ScrollableControl class and implement the IContainerControl interface. Implementation is added to the ActiveControl property and the ActivateControl method.

using namespace System;
using namespace System::Windows::Forms;
using namespace System::Drawing;

public ref class MyContainer: public ScrollableControl, public IContainerControl
   Control^ activeControl;

      // Make the container control Blue so it can be distinguished on the form.
      this->BackColor = Color::Blue;

      // Make the container scrollable.
      this->AutoScroll = true;

   property Control^ ActiveControl 
      // Add implementation to the IContainerControl.ActiveControl property.
      virtual Control^ get()
         return activeControl;

      virtual void set( Control^ value )

         // Make sure the control is a member of the ControlCollection.
         if ( this->Controls->Contains( value ) )
            activeControl = value;

   // Add implementations to the IContainerControl.ActivateControl(Control) method.
   virtual bool ActivateControl( Control^ active )
      if ( this->Controls->Contains( active ) )
         // Select the control and scroll the control into view if needed.
         active->Select(  );
         this->ScrollControlIntoView( active );
         this->activeControl = active;
         return true;

      return false;

.NET Framework
Available since 1.1
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