IContainerControl.ActivateControl Method

ContainerControl.IContainerControl.ActivateControl Method (Control)

.NET Framework (current version)
 

Activates the specified control.

Namespace:   System.Windows.Forms
Assembly:  System.Windows.Forms (in System.Windows.Forms.dll)

bool IContainerControl.ActivateControl(
	Control control
)

Parameters

control
Type: System.Windows.Forms.Control

The Control to activate.

Return Value

Type: System.Boolean

true if the control is successfully activated; otherwise, false.

The control parameter must be a child of the container control.

The following code example demonstrates how to inherit from the ScrollableControl class and implement the IContainerControl interface. Implementation is added to the ActiveControl property and the ActivateControl method.

using System;
using System.Windows.Forms;
using System.Drawing;

	public class MyContainer : ScrollableControl, IContainerControl
	{
		private Control activeControl;
		public MyContainer() 
		{
			// Make the container control Blue so it can be distinguished on the form.
			this.BackColor = Color.Blue;

			// Make the container scrollable.
			this.AutoScroll = true;
		}

		// Add implementation to the IContainerControl.ActiveControl property.
		public Control ActiveControl
		{
			get
			{
				return activeControl;
			}

			set
			{
				// Make sure the control is a member of the ControlCollection.
				if(this.Controls.Contains(value))
				{
					activeControl = value;
				}
			}
		}

		// Add implementations to the IContainerControl.ActivateControl(Control) method.
		public bool ActivateControl(Control active)
		{
			if(this.Controls.Contains(active))
			{
				// Select the control and scroll the control into view if needed.
				active.Select();
				this.ScrollControlIntoView(active);
				this.activeControl = active;
				return true;
			}
			return false;
		}
	}

.NET Framework
Available since 1.1
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