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Type::IsAutoLayout Property

.NET Framework (current version)
 

Gets a value indicating whether the fields of the current type are laid out automatically by the common language runtime.

Namespace:   System
Assembly:  mscorlib (in mscorlib.dll)

C#
C++
F#
VB
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public:
property bool IsAutoLayout {
	virtual bool get() sealed;
}

Property Value

Type: System::Boolean

true if the Attributes property of the current type includes TypeAttributes::AutoLayout; otherwise, false.

Implements

_Type::IsAutoLayout

This property is provided as a convenience. Alternatively, you can use the TypeAttributes::LayoutMaskenumeration value to select the type layout attributes, and then test whether TypeAttributes::AutoLayout is set. The TypeAttributes::AutoLayout,TypeAttributes::ExplicitLayout, and TypeAttributes::SequentialLayout enumeration values indicate the way the fields of the type are laid out in memory.

For dynamic types, you can specify TypeAttributes::AutoLayout when you create the type. In code, apply the StructLayoutAttribute attribute with the LayoutKind::Auto enumeration value to the type, to let the runtime determine the appropriate way to lay out the class.

System_CAPS_noteNote

You cannot use the GetCustomAttributes method to determine whether the StructLayoutAttribute has been applied to a type.

If the current Type represents a constructed generic type, this property applies to the generic type definition from which the type was constructed. For example, if the current Type represents MyGenericType<int> (MyGenericType(Of Integer) in Visual Basic), the value of this property is determined by MyGenericType<T>.

If the current Type represents a type parameter in the definition of a generic type or generic method, this property always returns false.

The following example creates an instance of the type and displays the IsAutoLayout property.

C#
C++
VB
Copy 
#using <System.dll>

using namespace System;
using namespace System::Reflection;
using namespace System::ComponentModel;
using namespace System::Runtime::InteropServices;

// The MyDemoAttribute class is selected as AutoLayout.

[StructLayoutAttribute(LayoutKind::Auto)]
public ref class MyDemoAttribute{};

void MyAutoLayoutMethod( String^ typeName )
{
   try
   {

      // Create an instance of the Type class using the GetType method.
      Type^ myType = Type::GetType( typeName );

      // Get and display the IsAutoLayout property of the
      // MyDemoAttribute instance.
      Console::WriteLine( "\nThe AutoLayout property for the MyDemoAttribute is {0}.", myType->IsAutoLayout );
   }
   catch ( Exception^ e ) 
   {
      Console::WriteLine( "\nAn exception occurred: {0}.", e->Message );
   }

}

int main()
{
   MyAutoLayoutMethod( "MyDemoAttribute" );
}

.NET Framework
Available since 1.1
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
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