CodeClass2::IsDerivedFrom Property (String^)

Visual Studio 2015

Gets a value indicating whether the code class has another code class as its base.

Namespace: EnvDTE80
Assembly: EnvDTE80 (in EnvDTE80.dll)

Syntax

property bool default[
	String^ FullName
] {
	bool get(String^ FullName);
}

Parameters

FullName: Type: System::String^
Required. The type to search for in the lineage of this type.

Property Value

Type: System::Boolean

A boolean value that is true if a code class has another code class as its base; false if otherwise.

Implements

CodeClass::IsDerivedFrom[String^]

Remarks

Note
The values of code model elements such as classes, structs, functions, attributes, delegates, and so forth can be non-deterministic after making certain kinds of edits, meaning that their values cannot be relied upon to always remain the same. For more information, see the section Code Model Element Values Can Change in Discovering Code by Using the Code Model (Visual Basic).

Examples

[Visual Basic]

Sub IsDerivedFromExample(ByVal dte As DTE2)
    ' Before running this example, open a code document from a project.
    Try
        Dim projItem As ProjectItem = dte.ActiveDocument.ProjectItem
        Dim cm As CodeModel = projItem.ContainingProject.CodeModel

        ' Create a new class.
        Dim cls1 As CodeClass = cm.AddClass("BaseClass", projItem.Name)

        ' Derive a class from the newly created class.
        Dim bases() As Object = {cls1.FullName}
        Dim cls2 As CodeClass = cm.AddClass("DerivedClass", _
            projItem.Name, -1, bases)

        Dim derived As String
        If cls1.IsDerivedFrom(cls2.FullName) Then
            derived &= cls1.Name & " is derived from " & _
                cls2.Name & vbCrLf
        Else
            derived &= cls1.Name & " is not derived from " & _
                cls2.Name & vbCrLf
        End If

        If cls2.IsDerivedFrom(cls1.FullName) Then
            derived &= cls2.Name & " is derived from " & _
                cls1.Name & vbCrLf
        Else
            derived &= cls2.Name & " is not derived from " & _
                cls1.Name & vbCrLf
        End If

        MsgBox(derived)
    Catch ex As Exception
        MsgBox(ex.Message)
    End Try
End Sub

[C#]

public void IsDerivedFromExample(DTE2 dte)
{
    // Before running this example, open a code document from 
    // a project.
    try
    {
        ProjectItem projItem = dte.ActiveDocument.ProjectItem;
        CodeModel cm = projItem.ContainingProject.CodeModel;

        // Create a new class.
        CodeClass cls1 = cm.AddClass("BaseClass", projItem.Name, -1, 
            null, null, vsCMAccess.vsCMAccessPublic);

        // Derive a class from the newly created class.
        object[] bases = {cls1.FullName};
        CodeClass cls2 = cm.AddClass("DerivedClass", projItem.Name, -1, 
            bases, null, vsCMAccess.vsCMAccessPublic);
        string derived = "";

        if (cls1.get_IsDerivedFrom(cls2.FullName))
            derived += cls1.Name + " is derived from " + 
                cls2.Name + "\n";
        else
            derived += cls1.Name + " is not derived from " + 
                cls2.Name + "\n";

        if (cls2.get_IsDerivedFrom(cls1.FullName))
            derived += cls2.Name + " is derived from " + 
                cls1.Name + "\n";
        else
            derived += cls2.Name + " is not derived from " + 
                cls1.Name + "\n";

        MessageBox.Show(derived);
    }
    catch (Exception ex)
    {
        MessageBox.Show(ex.Message);
    }
}