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How to: Apply a Transform to a BitmapImage

This example demonstrates how to apply a Transform to a BitmapImage.

'/// Create a BitmapImage and set it's DecodePixelWidth to 200. Use  ///// 
'/// this BitmapImage as a source for other BitmapSource objects.    ///// 
Dim myBitmapImage As New BitmapImage()

' BitmapSource objects like BitmapImage can only have their properties 
' changed within a BeginInit/EndInit block.
myBitmapImage.UriSource = New Uri("C:\Documents and Settings\All Users\Documents\My Pictures\Sample Pictures\Water Lilies.jpg")

' To save significant application memory, set the DecodePixelWidth or   
' DecodePixelHeight of the BitmapImage value of the image source to the desired  
' height or width of the rendered image. If you don't do this, the application will  
' cache the image as though it were rendered as its normal size rather then just  
' the size that is displayed. 
' Note: In order to preserve aspect ratio, set DecodePixelWidth 
' or DecodePixelHeight but not both.
myBitmapImage.DecodePixelWidth = 200

'///////////////// Create a BitmapSource that Rotates the image ////////////////////// 
' Use the BitmapImage created above as the source for a new BitmapSource object 
' that will be scaled to a different size. Create a new BitmapSource by    
' scaling the original one.                                                
' Note: New BitmapSource does not cache. It is always pulled when required. 
' Create the new BitmapSource that will be used to scale the size of the source. 
Dim myRotatedBitmapSource As New TransformedBitmap()

' BitmapSource objects like TransformedBitmap can only have their properties 
' changed within a BeginInit/EndInit block.

' Use the BitmapSource object defined above as the source for this BitmapSource. 
' This creates a "chain" of BitmapSource objects which essentially inherit from each other.
myRotatedBitmapSource.Source = myBitmapImage

' Flip the source 90 degrees.
myRotatedBitmapSource.Transform = New RotateTransform(90)