DateTime::Subtract Method (DateTime)
Updated: May 2010
Subtracts the specified date and time from this instance.
Assembly: mscorlib (in mscorlib.dll)
If the date and time of the current instance is earlier than value, the method returns a TimeSpan object that represents a negative time span. That is, the value of all of its non-zero properties (such as Days or Ticks) is negative.
The method does not consider the value of the Kind property of the two DateTime values when performing the subtraction. Before subtracting DateTime objects, ensure that the objects represent times in the same time zone. Otherwise, the result will include the difference between time zones.
The DateTimeOffset::Subtract(DateTimeOffset) method does consider the difference between time zones when performing the subtraction.
The following example demonstrates the Subtract method and the subtraction operator.
System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 ); System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 ); System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 ); // diff1 gets 185 days, 14 hours, and 47 minutes. System::TimeSpan diff1 = date2.Subtract( date1 ); // date4 gets 4/9/1996 5:55:00 PM. System::DateTime date4 = date3.Subtract( diff1 ); // diff2 gets 55 days 4 hours and 20 minutes. System::TimeSpan diff2 = date2 - date3; // date5 gets 4/9/1996 5:55:00 PM. System::DateTime date5 = date1 - diff2;
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The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.