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Strings.Mid Method (String, Int32, Int32)

Returns a string containing a specified number of characters from a string.

Namespace: Microsoft.VisualBasic
Assembly: Microsoft.VisualBasic (in microsoft.visualbasic.dll)

public static string Mid (
	string str,
	int Start,
	int Length
)
public static String Mid (
	String str, 
	int Start, 
	int Length
)
public static function Mid (
	str : String, 
	Start : int, 
	Length : int
) : String
Not applicable.

Parameters

str

Required. String expression from which characters are returned.

Start

Required. Integer expression. Starting position of the characters to return. If Start is greater than the number of characters in str, the Mid function returns a zero-length string (""). Start is one based.

Length

Optional. Integer expression. Number of characters to return. If omitted or if there are fewer than Length characters in the text (including the character at position Start), all characters from the start position to the end of the string are returned.

Return Value

Returns a string containing a specified number of characters from a string.

For more detailed information, see the Visual Basic topic Mid Function (Visual Basic).

To determine the number of characters in str, use the Len function.

Visual Basic has a Mid function and a Mid statement. These elements both operate on a specified number of characters in a string, but the Mid function returns the characters while the Mid statement replaces the characters. For more information, see Mid Statement.

NoteNote:

The MidB function in previous versions of Visual Basic returns a string in bytes rather than characters. It is used primarily for converting strings in double-byte character set (DBCS) applications. All Visual Basic strings are in Unicode, and MidB is no longer supported.

This example uses the Mid function to return a specified number of characters from a string.

' Creates text string.
Dim TestString As String = "Mid Function Demo"
' Returns "Mid".
Dim FirstWord As String = Mid(TestString, 1, 3)
' Returns "Demo".
Dim LastWord As String = Mid(TestString, 14, 4)
' Returns "Function Demo".
Dim MidWords As String = Mid(TestString, 5)

Windows 98, Windows Server 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

The Microsoft .NET Framework 3.0 is supported on Windows Vista, Microsoft Windows XP SP2, and Windows Server 2003 SP1.

.NET Framework

Supported in: 3.0, 2.0, 1.1, 1.0

.NET Compact Framework

Supported in: 2.0, 1.0

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