|Important||This document may not represent best practices for current development, links to downloads and other resources may no longer be valid. Current recommended version can be found here. ArchiveDisclaimer|
Reads a single line from an open sequential file and assigns it to a String variable.
Required. Any valid file number.
|Exception type||Error number||Condition|
End of file reached.
FileNumber does not exist.
See the "Error number" column if you are upgrading Visual Basic 6.0 applications that use unstructured error handling. (You can compare the error number against the.) However, when possible, you should consider replacing such error control with .
The LineInput function is provided for backward compatibility and may have an impact on performance. For non-legacy applications, the My.Computer.FileSystem object provides better performance. For more information, see.
Data read with LineInput is usually written to a file with Print.
When reading from files, do not make decisions about the contents of a file based on the file name extension. For example, a file named Form1.vb may not be a Visual Basic source file.
The LineInput function reads from a file one character at a time until it encounters a carriage return (Chr(13)) or carriage return/line feed (Chr(13) + Chr(10)) sequence. Carriage return/line feed sequences are skipped rather than appended to the character string.
Reading from a file with the LineInput function requires Read access from theenumeration.
This example uses the LineInput function to read a line from a sequential file and assign it to a variable. This example assumes that TestFile is a text file with a few lines of sample data.
Assembly: Visual Basic Runtime Library (in Microsoft.VisualBasic.dll)