Mid Method (String, Int32)
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Strings.Mid Method (String, Int32)


Returns a string that contains all the characters starting from a specified position in a string.

Namespace:   Microsoft.VisualBasic
Assembly:  Microsoft.VisualBasic (in Microsoft.VisualBasic.dll)

public static string Mid(
	string str,
	int Start


Type: System.String

Required. String expression from which characters are returned.

Type: System.Int32

Required. Integer expression. Starting position of the characters to return. If Start is greater than the number of characters in str, the Mid function returns a zero-length string (""). Start is one-based.

Return Value

Type: System.String

A string that consists of all the characters starting from the specified position in the string.

Exception Condition

Start <= 0 or Length < 0.

To determine the number of characters in str, use the Len function.

Visual Basic has a Mid function and a Mid statement. These elements both operate on a specified number of characters in a string, but the Mid function returns the characters while the Mid statement replaces the characters. For more information, see Mid Statement.


The MidB function in previous versions of Visual Basic returns a string in bytes rather than characters. It is used primarily for converting strings in double-byte character set (DBCS) applications. All Visual Basic strings are in Unicode, and MidB is no longer supported.

The last line in this example uses this overload of the Mid function to return the fifth and subsequent characters from a string.

' Creates text string.
Dim TestString As String = "Mid Function Demo"
' Returns "Mid".
Dim FirstWord As String = Mid(TestString, 1, 3)
' Returns "Demo".
Dim LastWord As String = Mid(TestString, 14, 4)
' Returns "Function Demo".
Dim MidWords As String = Mid(TestString, 5)

.NET Framework
Available since 1.1
Available since 2.0
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