EnumerableLast Method
 

Returns the last element of a sequence.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static TSource Last<TSource>(
	this IEnumerable<TSource> source
)
public:
generic<typename TSource>
[ExtensionAttribute]
static TSource Last(
	IEnumerable<TSource>^ source
)
static member Last<'TSource> : 
        source:IEnumerable<'TSource> -> 'TSource
<ExtensionAttribute>
Public Shared Function Last(Of TSource) (
	source As IEnumerable(Of TSource)
) As TSource

Parameters

source
Type:

An IEnumerable to return the last element of.

Return Value

Type: TSource

The value at the last position in the source sequence.

Type Parameters

TSource

The type of the elements of source.

Exception Condition
ArgumentNullException

source is null.

InvalidOperationException

The source sequence is empty.

The Last method throws an exception if source contains no elements. To instead return a default value when the source sequence is empty, use the LastOrDefault method.

The following code example demonstrates how to use Last to return the last element of an array.

int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54, 
                    83, 23, 87, 67, 12, 19 };

int last = numbers.Last();

Console.WriteLine(last);

/*
 This code produces the following output:

 19
*/
' Create an array of integers.
Dim numbers() As Integer =
{9, 34, 65, 92, 87, 435, 3, 54, 83, 23, 87, 67, 12, 19}

' Get the last item in the array.
Dim last As Integer = numbers.Last()

' Display the result.
MsgBox(last)

' This code produces the following output:
'
' 19
Universal Windows Platform
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1
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