shared_ptr::operator->

  • Article

Gets a pointer to the designated value.

Ty *operator->() const;

Remarks

The selection operator returns get(), so that the expression sp->member behaves the same as (sp.get())->member where sp is an object of class shared_ptr<Ty>. Hence, the stored pointer must not be null, and Ty must be a class, structure, or union type with a member member.

Example

 

// std_tr1__memory__shared_ptr_operator_ar.cpp 
// compile with: /EHsc 
#include <memory> 
#include <iostream> 
 
typedef std::pair<int, int> Mypair; 
int main() 
    { 
    std::shared_ptr<Mypair> sp0(new Mypair(1, 2)); 
 
    std::cout << "sp0->first == " << sp0->first << std::endl; 
    std::cout << "sp0->second == " << sp0->second << std::endl; 
 
    return (0); 
    } 
 

sp0->first == 1
sp0->second == 2

Requirements

Header: <memory>

Namespace: std

See Also

Reference

shared_ptr Class

shared_ptr::get

shared_ptr::operator*