Queryable.Max<TSource> Method (IQueryable<TSource>)


Returns the maximum value in a generic IQueryable<T>.

Namespace:   System.Linq
Assembly:  System.Core (in System.Core.dll)

public static TSource Max<TSource>(
	this IQueryable<TSource> source


Type: System.Linq.IQueryable<TSource>

A sequence of values to determine the maximum of.

Return Value

Type: TSource

The maximum value in the sequence.

Type Parameters


The type of the elements of source.

Exception Condition

source is null.

The Max<TSource>(IQueryable<TSource>) method generates a MethodCallExpression that represents calling Max<TSource>(IQueryable<TSource>) itself as a constructed generic method. It then passes the MethodCallExpression to the Execute<TResult>(Expression) method of the IQueryProvider represented by the Provider property of the source parameter.

The query behavior that occurs as a result of executing an expression tree that represents calling Max<TSource>(IQueryable<TSource>) depends on the implementation of the type of the source parameter. The expected behavior is that it returns the maximum value in source.

The following code example demonstrates how to use Max<TSource>(IQueryable<TSource>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.AsQueryable().Max();

Console.WriteLine("The largest number is {0}.", max);

    This code produces the following output:

    The largest number is 4294967296.

Universal Windows Platform
Available since 4.5
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Available since 2.0
Windows Phone Silverlight
Available since 7.1
Windows Phone
Available since 8.1
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