Enumerable.Sum(TSource) Method (IEnumerable(TSource), Func(TSource, Int32))
Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.
Assemblies: System.Linq (in System.Linq.dll)
System.Core (in System.Core.dll)
static member Sum : source:IEnumerable<'TSource> * selector:Func<'TSource, int> -> int
The type of the elements of source.
- Type: System.Collections.Generic.IEnumerable()
A sequence of values that are used to calculate a sum.
Return ValueType: System.Int32
The sum of the projected values.
Usage NoteIn Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable(). When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).
This method returns zero if source contains no elements.
You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.
In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.
The following code example demonstrates how to use Sum(TSource)(IEnumerable(TSource), Func(TSource, Double)) to sum the projected values of a sequence.
This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.