# 7.9.10 The as operator

**Visual Studio .NET 2003**

The `as`

operator is used to explicitly convert a value to a given reference type using a reference conversion or a boxing conversion. Unlike a cast expression (Section 7.6.6), the `as`

operator never throws an exception. Instead, if the indicated conversion is not possible, the resulting value is `null`

.

In an operation of the form `e`

`as`

`T`

, `e`

must be an expression and `T`

must be a reference type. The type of the result is `T`

, and the result is always classified as a value. The operation is evaluated as follows:

- If the compile-time type of
`e`

is the same as`T`

, the result is simply the value of`e`

. - Otherwise, if an implicit reference conversion (Section 6.1.4) or boxing conversion (Section 6.1.5) exists from the compile-time type of e to
`T`

, this conversion is performed and becomes the result of the operation. - Otherwise, if an explicit reference conversion (Section 6.2.3) exists from the compile-time type of e to T, a dynamic type check is performed:
- If the value of e is
`null`

, the result is the value`null`

with the compile-time type`T`

. - Otherwise, let
`R`

be the run-time type of the instance referenced by`e`

. If`R`

and`T`

are the same type, if`R`

is a reference type and an implicit reference conversion from`R`

to`T`

exists, or if`R`

is a value type and`T`

is an interface type that is implemented by`R`

, the result is the reference given by`e`

with the compile-time type`T`

. - Otherwise, the result is the value
`null`

with the compile-time type`T`

.

- If the value of e is
- Otherwise, the indicated conversion is never possible, and a compile-time error occurs.

Note that the `as`

operator only performs reference conversions and boxing conversions. Other conversions, such as user defined conversions, are not possible with the `as`

operator and should instead be performed using cast expressions.

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