在指定
String 数组的每个元素之间串联指定的分隔符
String，从而产生单个串联的字符串。
命名空间:System
程序集:mscorlib（在 mscorlib.dll 中）
Public Shared Function Join ( _
separator As String, _
value As String() _
) As String
Dim separator As String
Dim value As String()
Dim returnValue As String
returnValue = String.Join(separator, value)
public static string Join (
string separator,
string[] value
)
public:
static String^ Join (
String^ separator,
array<String^>^ value
)
public static String Join (
String separator,
String[] value
)
public static function Join (
separator : String,
value : String[]
) : String
参数
- separator
String。
- value
一个 String 数组。
返回值
String，包含与 separator 字符串交错的 value 的元素。
例如，如果 separator 为“,”且 value 的元素为“apple”、“orange”、“grape”和“pear”，则 Join(separator, value) 返回“apple, orange, grape, pear”。
如果 separator 为 空引用（在 Visual Basic 中为 Nothing），则改用空字符串 (Empty)。
下面的代码示例说明了 Join 方法。
Imports System
Public Class JoinTest
Public Shared Sub Main()
Console.WriteLine(MakeLine(0, 5, ", "))
Console.WriteLine(MakeLine(1, 6, " "))
Console.WriteLine(MakeLine(9, 9, ": "))
Console.WriteLine(MakeLine(4, 7, "< "))
End Sub 'Main
Private Shared Function MakeLine(initVal As Integer, multVal As Integer, sep As String) As String
Dim sArr(10) As String
Dim i As Integer
For i = initVal To (initVal + 10) - 1
sArr((i - initVal)) = [String].Format("{0,-3}", i * multVal)
Next i
Return [String].Join(sep, sArr)
End Function 'MakeLine
End Class 'JoinTest
using System;
public class JoinTest {
public static void Main() {
Console.WriteLine(MakeLine(0, 5, ", "));
Console.WriteLine(MakeLine(1, 6, " "));
Console.WriteLine(MakeLine(9, 9, ": "));
Console.WriteLine(MakeLine(4, 7, "< "));
}
private static string MakeLine(int initVal, int multVal, string sep) {
string [] sArr = new string [10];
for (int i = initVal; i < initVal + 10; i++)
sArr[i - initVal] = String.Format("{0,-3}", i * multVal);
return String.Join(sep, sArr);
}
}
using namespace System;
String^ MakeLine( int initVal, int multVal, String^ sep )
{
array<String^>^sArr = gcnew array<String^>(10);
for ( int i = initVal; i < initVal + 10; i++ )
sArr[ i - initVal ] = String::Format( "{0, -3}", i * multVal );
return String::Join( sep, sArr );
}
int main()
{
Console::WriteLine( MakeLine( 0, 5, ", " ) );
Console::WriteLine( MakeLine( 1, 6, " " ) );
Console::WriteLine( MakeLine( 9, 9, ": " ) );
Console::WriteLine( MakeLine( 4, 7, "< " ) );
}
import System.*;
public class JoinTest
{
public static void main(String[] args)
{
Console.WriteLine(MakeLine(0, 5, ", "));
Console.WriteLine(MakeLine(1, 6, " "));
Console.WriteLine(MakeLine(9, 9, ": "));
Console.WriteLine(MakeLine(4, 7, "< "));
} //main
private static String MakeLine(int initVal, int multVal, String sep)
{
String sArr[] = new String[10];
for (int i = initVal; i < initVal + 10; i++) {
sArr.set_Item((i - initVal), String.Format("{0,-3}",
(Int32)(i * multVal)));
}
return String.Join(sep, sArr);
} //MakeLine
} //JoinTest
import System;
public class JoinTest {
public static function Main() : void {
Console.WriteLine(MakeLine(0, 5, ", "));
Console.WriteLine(MakeLine(1, 6, " "));
Console.WriteLine(MakeLine(9, 9, ": "));
Console.WriteLine(MakeLine(4, 7, "< "));
}
private static function MakeLine(initVal : int, multVal : int, sep : String) : String {
var sArr : String [] = new String [10];
for (var i : int = initVal; i < initVal + 10; i++)
sArr[i - initVal] = String.Format("{0,-3}", i * multVal);
return String.Join(sep, sArr);
}
}
JoinTest.Main();
Windows 98、Windows 2000 SP4、Windows CE、Windows Millennium Edition、Windows Mobile for Pocket PC、Windows Mobile for Smartphone、Windows Server 2003、Windows XP Media Center Edition、Windows XP Professional x64 Edition、Windows XP SP2、Windows XP Starter Edition
.NET Framework 并不是对每个平台的所有版本都提供支持。有关受支持版本的列表，请参见系统要求。
.NET Framework
受以下版本支持：2.0、1.1、1.0
.NET Compact Framework
受以下版本支持：2.0、1.0