XElement.DescendantNodesAndSelf Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Returns a collection of nodes that contain this element, and all descendant nodes of this element, in document order.
public:
System::Collections::Generic::IEnumerable<System::Xml::Linq::XNode ^> ^ DescendantNodesAndSelf();
public System.Collections.Generic.IEnumerable<System.Xml.Linq.XNode> DescendantNodesAndSelf ();
member this.DescendantNodesAndSelf : unit -> seq<System.Xml.Linq.XNode>
Public Function DescendantNodesAndSelf () As IEnumerable(Of XNode)
Returns
An IEnumerable<T> of XNode that contain this element, and all descendant nodes of this element, in document order.
Examples
The following example creates an XML tree, and then uses this .
XElement xmlTree = new XElement("Root",
// Attributes are not nodes, so will not be returned by DescendantNodesAndSelf.
new XAttribute("Att1", "AttributeContent"),
new XElement("Child",
new XText("Some text"),
new XElement("GrandChild", "element content")
)
);
IEnumerable<XNode> dnas =
from node in xmlTree.DescendantNodesAndSelf()
select node;
foreach (XNode node in dnas)
{
if (node is XElement)
Console.WriteLine((node as XElement).Name);
else
Console.WriteLine(node);
}
Dim xmlTree As XElement = _
<Root Att1="AttributeContent">
<Child>Some text<GrandChild>element content</GrandChild>
</Child>
</Root>
Dim dnas As IEnumerable(Of XNode) = _
From node In xmlTree.DescendantNodesAndSelf() _
Select node
For Each node In dnas
If TypeOf node Is XElement Then
Console.WriteLine(DirectCast(node, XElement).Name)
Else
Console.WriteLine(node)
End If
Next
This example produces the following output:
Root
Child
Some text
GrandChild
element content
Remarks
This method uses deferred execution.
Applies to
See also
GitHub에서 Microsoft와 공동 작업
이 콘텐츠의 원본은 GitHub에서 찾을 수 있으며, 여기서 문제와 끌어오기 요청을 만들고 검토할 수도 있습니다. 자세한 내용은 참여자 가이드를 참조하세요.
.NET
피드백
https://aka.ms/ContentUserFeedback
출시 예정: 2024년 내내 콘텐츠에 대한 피드백 메커니즘으로 GitHub 문제를 단계적으로 폐지하고 이를 새로운 피드백 시스템으로 바꿀 예정입니다. 자세한 내용은 다음을 참조하세요.다음에 대한 사용자 의견 제출 및 보기