Enumerable.Min Method (IEnumerable<Int32>)
Returns the minimum value in a sequence of Int32 values.
Namespace: System.Linq
Assembly: System.Core (in System.Core.dll)
Parameters
- source
- Type: System.Collections.Generic.IEnumerable<Int32>
A sequence of Int32 values to determine the minimum value of.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Int32>. When you use instance method syntax to call this method, omit the first parameter.| Exception | Condition |
|---|---|
| ArgumentNullException | source is null. |
| InvalidOperationException | source contains no elements. |
The Min(IEnumerable<Int32>) method uses the Int32 implementation of IComparable<T> to compare values.
In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.
The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.
Note: |
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This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type. |
For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.
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