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How to: Explicitly Throw Exceptions

You can explicitly throw an exception using the throw statement. You can also throw a caught exception again using the throw statement. It is good coding practice to add information to an exception that is re-thrown to provide more information when debugging.

The following code example uses a try/catch block to catch a possible FileNotFoundException. Following the try block is a catch block that catches the FileNotFoundExceptionand writes a message to the console if the data file is not found. The next statement is the throw statement that throws a new FileNotFoundException and adds text information to the exception.

using System;
using System.IO;

public class ProcessFile
{
   public static void Main()
      {
      FileStream fs = null;
      try   
      {
         //Opens a text tile.
         fs = new FileStream(@"C:\temp\data.txt", FileMode.Open);
         StreamReader sr = new StreamReader(fs);
         string line;

         //A value is read from the file and output to the console.
         line = sr.ReadLine();
         Console.WriteLine(line);
      }
      catch(FileNotFoundException e)
      {
         Console.WriteLine("[Data File Missing] {0}", e);
         throw new FileNotFoundException(@"data.txt not in c:\temp directory]",e);
      }
      finally
      {
         if (fs != null) 
            fs.Close();
      }
   }
}

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