__m64_muladd64hi, __m64_muladd64hi_u
Microsoft Specific
Compute the high 64 bits of the expression a*b+c.
__m64 __m64_muladd64hi( __m64 a, __m64 b, __m64 c ); __m64 __m64_muladd64hi_u( __m64 a, __m64 b, __m64 c );
// muladd64hi.c
// processor: IPF
#include <stdio.h>
#include <intrin.h>
#include <limits.h>
#pragma intrinsic(__m64_muladd64hi, __m64_muladd64hi_u, __m64_muladd64lo)
int main()
{
__m64 a, b, c, result;
a.m64_i64 = 2I64;
b.m64_i64 = _I64_MAX;
c.m64_i64 = _I64_MAX;
result = __m64_muladd64hi(a, b, c);
printf_s("0x%I64x", result.m64_i64);
result = __m64_muladd64lo(a, b, c);
printf_s("%I64x\n", result.m64_i64);
b.m64_u64 = _UI64_MAX;
c.m64_u64 = _UI64_MAX;
result = __m64_muladd64hi_u(a, b, c);
printf_s("0x%I64x", result.m64_u64);
result = __m64_muladd64lo(a, b, c);
printf_s("%I64x", result.m64_u64);
return 0;
}
0x17ffffffffffffffd 0x2fffffffffffffffd