Color.FromArgb method

Creates a new Color structure by using the specified sRGB alpha channel and color channel values.

Syntax

public static Color FromArgb(
  byte a, 
  byte r, 
  byte g, 
  byte b
)

Parameters

a

Type: System.Byte

The alpha channel, A, of the new color. The value must be between 0 and 255.

r

Type: System.Byte

The red channel, R, of the new color. The value must be between 0 and 255.

g

Type: System.Byte

The green channel, G, of the new color. The value must be between 0 and 255.

b

Type: System.Byte

The blue channel, B, of the new color. The value must be between 0 and 255.

Return value

Type: Color

A Color structure with the specified values.

Remarks

The FromArgb method requires you to specify the alpha channel. The alpha channel of a color determines the amount of transparency of the color. An alpha value of 255 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.

Requirements

See also

Color

Build date: 2/25/2013