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Video.Open Method ()

Loads a new file into the Video object.

Overload List

public void Open(string);
public void Open(string, bool);
public void Open(Uri);
public void Open(Uri, bool);

Remarks

Exceptions

DirectXException

For more information on the cause of this exception, reference the DirectXException.ErrorCode and DirectXException.ErrorString properties to the AudioVideoPlayback error code table.