NotifyIcon.Visible Property

Gets or sets a value indicating whether the icon is visible in the notification area of the taskbar.

Namespace:  System.Windows.Forms
Assembly:  System.Windows.Forms (in System.Windows.Forms.dll)

member Visible : bool with get, set

Property Value

Type: System.Boolean
true if the icon is visible in the notification area; otherwise, false. The default value is false.

Since the default value is false, in order for the icon to show up in the notification area, you must set the Visible property to true.

The following code example demonstrates using the NotifyIcon class to display an icon for an application in the notification area. The example demonstrates setting the Icon, ContextMenu, Text, and Visible properties and handling the DoubleClick event. A ContextMenu with an Exit item on it is assigned to the NotifyIcon.ContextMenu property, which allows the user to close the application. When the DoubleClick event occurs, the application form is activated by calling the Form.Activate method.

No code example is currently available or this language may not be supported.

.NET Framework

Supported in: 4.5.2, 4.5.1, 4.5, 4, 3.5, 3.0, 2.0, 1.1, 1.0

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

Windows 8.1, Windows Server 2012 R2, Windows 8, Windows Server 2012, Windows 7, Windows Vista SP2, Windows Server 2008 (Server Core Role not supported), Windows Server 2008 R2 (Server Core Role supported with SP1 or later; Itanium not supported)

The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

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