BigInteger.Max Method
.NET Framework 4
Returns the larger of two BigInteger values.
Assembly: System.Numerics (in System.Numerics.dll)
Parameters
- left
- Type: System.Numerics.BigInteger
The first value to compare.
- right
- Type: System.Numerics.BigInteger
The second value to compare.
The following example uses the Max method to select the largest number in an array of BigInteger values.
using System; using System.Numerics; public class Example { public static void Main() { BigInteger[] numbers = { Int64.MaxValue * BigInteger.MinusOne, BigInteger.MinusOne, 10359321239000, BigInteger.Pow(103988, 2), BigInteger.Multiply(Int32.MaxValue, Int16.MaxValue), BigInteger.Add(BigInteger.Pow(Int64.MaxValue, 2), BigInteger.Pow(Int32.MaxValue, 2)) }; if (numbers.Length < 2) { Console.WriteLine("Cannot determine which is the larger of {0} numbers.", numbers.Length); return; } BigInteger largest = numbers[numbers.GetLowerBound(0)]; for (int ctr = numbers.GetLowerBound(0) + 1; ctr <= numbers.GetUpperBound(0); ctr++) largest = BigInteger.Max(largest, numbers[ctr]); Console.WriteLine("The values:"); foreach (BigInteger number in numbers) Console.WriteLine("{0,55:N0}", number); Console.WriteLine("\nThe largest number of the series is:"); Console.WriteLine(" {0:N0}", largest); } } // The example displays the following output: // The values: // -9,223,372,036,854,775,807 // -1 // 10,359,321,239,000 // 10,813,504,144 // 70,366,596,661,249 // 85,070,591,730,234,615,852,008,593,798,364,921,858 // // The largest number of the series is: // 85,070,591,730,234,615,852,008,593,798,364,921,858
Windows 7, Windows Vista SP1 or later, Windows XP SP3, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.