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# Enumerable.Sum Method

Computes the sum of a sequence of numeric values.

This member is overloaded. For complete information about this member, including syntax, usage, and examples, click a name in the overload list.

Name | Description | |
---|---|---|

Sum(IEnumerable<Decimal>) | Computes the sum of a sequence of Decimal values. | |

Sum(IEnumerable<Nullable<Decimal>>) | Computes the sum of a sequence of nullable Decimal values. | |

Sum(IEnumerable<Double>) | Computes the sum of a sequence of Double values. | |

Sum(IEnumerable<Nullable<Double>>) | Computes the sum of a sequence of nullable Double values. | |

Sum(IEnumerable<Int32>) | Computes the sum of a sequence of Int32 values. | |

Sum(IEnumerable<Nullable<Int32>>) | Computes the sum of a sequence of nullable Int32 values. | |

Sum(IEnumerable<Int64>) | Computes the sum of a sequence of Int64 values. | |

Sum(IEnumerable<Nullable<Int64>>) | Computes the sum of a sequence of nullable Int64 values. | |

Sum(IEnumerable<Nullable<Single>>) | Computes the sum of a sequence of nullable Single values. | |

Sum(IEnumerable<Single>) | Computes the sum of a sequence of Single values. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Decimal>) | Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Double>) | Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Int32>) | Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Int64>) | Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Nullable<Decimal>>) | Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Nullable<Double>>) | Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Nullable<Int32>>) | Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Nullable<Int64>>) | Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Nullable<Single>>) | Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence. | |

Sum<TSource>(IEnumerable<TSource>, Func<TSource, Single>) | Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence. |

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