IXmlSerializable.ReadXml Method
Generates an object from its XML representation.
Assembly: System.Xml (in System.Xml.dll)
The ReadXml method must reconstitute your object using the information that was written by the WriteXml method.
When this method is called, the reader is positioned at the start of the element that wraps the information for your type. That is, just before the start tag that indicates the beginning of a serialized object. When this method returns, it must have read the entire element from beginning to end, including all of its contents. Unlike the WriteXml method, the framework does not handle the wrapper element automatically. Your implementation must do so. Failing to observe these positioning rules may cause code to generate unexpected runtime exceptions or corrupt data.
When implementing this method, you should consider the possibility that a malicious user might provide a well-formed but invalid XML representation in order to disable or otherwise alter the behavior of your application.
The following example illustrates an implementation of the ReadXml method.
The following example illustrates the use of the XmlSerializer class to deserialize this object.
using System; using System.IO; using System.Xml.Serialization; public class Reader { public static void Main() { XmlSerializer serializer = new XmlSerializer(typeof(Person)); FileStream file = new FileStream("test.xml", FileMode.Open); Person aPerson = (Person) serializer.Deserialize(file); Console.WriteLine(aPerson); } }
Windows 7, Windows Vista SP1 or later, Windows XP SP3, Windows XP SP2 x64 Edition, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
The previous comment notes that ReadElementString() would do this, but perhaps being more explicit would help with the example.
- 11/26/2010
- Olly A
The example implementation shown above didn't work for me, but this did:
public void ReadXml (XmlReader reader)
{
personName = reader.ReadElementString();
}
It seems that the call to reader.ReadString() does not properly position the reader at the next element.
- 7/19/2010
- JasonS007