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Color.FromRgb Method

.NET Framework 3.5

Creates a new Color structure by using the specified sRGB color channel values.

Namespace:  System.Windows.Media
Assembly:  PresentationCore (in PresentationCore.dll)
C#
C++
JScript
VB
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public static Color FromRgb(
	byte r,
	byte g,
	byte b
)
XAML
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You cannot use methods in XAML.

Parameters

r
Type: System.Byte
The sRGB red channel, R, of the new color.
g
Type: System.Byte
The sRGB green channel, G, of the new color.
b
Type: System.Byte
The sRGB blue channel, B, of the new color.

Return Value

Type: System.Windows.Media.Color
A Color structure with the specified values and an alpha channel value of 1.

The FromArgb method allows you to specify the alpha channel; the FromRgb method uses a default value of 1 for the alpha channel.

The alpha channel of a color determines the amount of transparency of the color. An alpha value of 1 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.

The sRGB channels (A, R, G, B) and the ScRGB channels (ScA, ScR, ScG, ScB) of the Color structure are synchronized properties. For example, when R, the sRGB red channel, is modified the ScRGB red channel, ScR, is transformed to the equivalent value.

The following example shows how to use the FromRgb method to create a Color structure.

C#
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private Color FromRgbExample()
{
    // Create a green color using the FromRgb static method.
    Color myRgbColor = new Color();
    myRgbColor = Color.FromRgb(0, 255, 0);
    return myRgbColor;
}

Windows 7, Windows Vista, Windows XP SP2, Windows Server 2008 R2, Windows Server 2008, Windows Server 2003

The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

.NET Framework

Supported in: 3.5, 3.0
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