DateTimePicker.ShowCheckBox Property
.NET Framework 4
Gets or sets a value indicating whether a check box is displayed to the left of the selected date.
Assembly: System.Windows.Forms (in System.Windows.Forms.dll)
The following code example creates an new instance of a DateTimePicker control and initializes it. The control's CustomFormat property is set. Also, the ShowCheckBox property is set so that the control displays a CheckBox, and the ShowUpDown property is set so that the control is displayed as a spin button control (also known as an up-down control).
public void CreateMyDateTimePicker() { // Create a new DateTimePicker control and initialize it. DateTimePicker dateTimePicker1 = new DateTimePicker(); // Set the MinDate and MaxDate. dateTimePicker1.MinDate = new DateTime(1985, 6, 20); dateTimePicker1.MaxDate = DateTime.Today; // Set the CustomFormat string. dateTimePicker1.CustomFormat = "MMMM dd, yyyy - dddd"; dateTimePicker1.Format = DateTimePickerFormat.Custom; // Show the CheckBox and display the control as an up-down control. dateTimePicker1.ShowCheckBox = true; dateTimePicker1.ShowUpDown = true; }
Windows 7, Windows Vista SP1 or later, Windows XP SP3, Windows XP SP2 x64 Edition, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.