FontWeight.Compare Method
.NET Framework 4.5
Compares two instances of FontWeight.
Namespace: System.Windows
Assembly: PresentationCore (in PresentationCore.dll)
Parameters
- left
- Type: System.Windows.FontWeight
The first FontWeight object to compare.
- right
- Type: System.Windows.FontWeight
The second FontWeight object to compare.
Return Value
Type: System.Int32An Int32 value that indicates the relationship between the two instances of FontWeight. When the return value is less than zero, left is less than right. When this value is zero, it indicates that both operands are equal. When the value is greater than zero, it indicates that left is greater than right.
In the following code example, the Compare method is used to evaluate two FontWeight objects.
// Return the typefaces for the selected font family name and font values. Typeface typeface1 = new Typeface(new FontFamily("Arial"), FontStyles.Normal, FontWeights.Normal, FontStretches.Normal); Typeface typeface2 = new Typeface(new FontFamily("Arial"), FontStyles.Normal, FontWeights.UltraBold, FontStretches.Normal); if (FontWeight.Compare(typeface1.Weight, typeface2.Weight) < 0) { // Code execution follows this path because // the FontWeight of typeface1 (Normal) is less than of typeface2 (UltraBold). }
Windows 8, Windows Server 2012, Windows 7, Windows Vista SP2, Windows Server 2008 (Server Core Role not supported), Windows Server 2008 R2 (Server Core Role supported with SP1 or later; Itanium not supported)
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.