Namespace:
System.Windows.Controls
Assembly:
PresentationFramework (in PresentationFramework.dll)
'Usage
Dim instance As ItemsControl
Dim value As ItemContainerGenerator
value = instance.ItemContainerGenerator
'Declaration
<BindableAttribute(False)> _
<BrowsableAttribute(False)> _
Public ReadOnly Property ItemContainerGenerator As ItemContainerGenerator
You cannot set this property in XAML.
An ItemContainerGenerator is responsible for generating the user interface (UI) for its host, such as an ItemsControl. It maintains the association between the items in the data view of the control and the corresponding UIElement objects.
If you need to get a specific ListBoxItem at a particular index in a ListBox, you can use an ItemContainerGenerator.
The following example shows a ListBox and its items.
<ListBox Margin="10,0,0,5" Name="lb" VerticalAlignment="Top" Grid.Column="0" Grid.Row="2">
<ListBoxItem>Item 0</ListBoxItem>
<ListBoxItem>Item 1</ListBoxItem>
<ListBoxItem>Item 2</ListBoxItem>
<ListBoxItem>Item 3</ListBoxItem>
</ListBox>
The following example shows how to retrieve the item by specifying the index of the item in the ContainerFromIndex property of the ItemContainerGenerator.
Private Sub GetIndex0(ByVal Sender As Object, ByVal e As RoutedEventArgs)
Dim lbi As ListBoxItem = CType( _
lb.ItemContainerGenerator.ContainerFromIndex(0), ListBoxItem)
Item.Content = "The contents of the item at index 0 are: " + _
(lbi.Content.ToString()) + "."
End Sub
After you have retrieved the list box item, you can display the contents of the item, as shown in the following example.
Item.Content = "The contents of the item at index 0 are: " + _
(lbi.Content.ToString()) + "."
Windows 7, Windows Vista, Windows XP SP2, Windows Server 2008 R2, Windows Server 2008, Windows Server 2003
The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
.NET Framework
Supported in: 3.5, 3.0
Reference
Other Resources