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ContextMenuService.ShowOnDisabled Attached Property

Gets or sets a value that indicates whether the ContextMenu should be shown when its parent is grayed out.

Namespace: System.Windows.Controls
Assembly: PresentationFramework (in PresentationFramework.dll)
XML Namespace:  http://schemas.microsoft.com/winfx/2006/xaml/presentation

See ContextMenuService.GetShowOnDisabled, ContextMenuService.SetShowOnDisabled
See ContextMenuService.GetShowOnDisabled, ContextMenuService.SetShowOnDisabled
See ContextMenuService.GetShowOnDisabled, ContextMenuService.SetShowOnDisabled
<object ContextMenuService.ShowOnDisabled="bool" .../>

Property Value

A Boolean value that is true if the ContextMenu should be shown when its parent is grayed out; false otherwise.

Identifier Field

ShowOnDisabledProperty, registered as Attached

Metadata Flags

None

This example creates and displays a ContextMenu on a disabled or grayed out button.

<Button Height="30" Content="Disabled Button" IsEnabled="False" 
        ContextMenuService.ShowOnDisabled="True">
  <Button.ContextMenu>
    <ContextMenu>
      <MenuItem Header="Edit">
        <MenuItem Header="Cut"/>
        <MenuItem Header="Copy"/>
        <MenuItem Header="Paste"/>
        <Separator/>
        <MenuItem Header="Context Menu item with ToolTip">
          <MenuItem.ToolTip>
            <ToolTip>
              Some information.
            </ToolTip>
          </MenuItem.ToolTip>
        </MenuItem>
      </MenuItem>
    </ContextMenu>
  </Button.ContextMenu>
</Button>

Windows 98, Windows Server 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

The Microsoft .NET Framework 3.0 is supported on Windows Vista, Microsoft Windows XP SP2, and Windows Server 2003 SP1.

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