The following code example demonstrates how to use the PostBackUrl property to perform a cross-page post. When the user clicks the Button control, the page posts the value entered in the text box to the target page specified by the PostBackUrl property. To run this sample, you must also create a file for the target page in the same directory as this code example. The code for target page is provided in the next example.
<%@ page language="VB" %>
<html>
<head id="Head1" runat="server">
<title>Button.PostBackUrl Example</title>
</head>
<body>
<form id="Form1" runat="server">
<h3>Button.PostBackUrl Example</h3>
Enter a value to post:
<asp:textbox id="TextBox1"
runat=Server>
</asp:textbox>
<br><br />
<asp:button id="Button1"
text="Post back to this page"
runat="Server">
</asp:button>
<br /><br />
<asp:button id="Button2"
text="Post value to another page"
postbackurl="Button.PostBackUrlPage2vb.aspx"
runat="Server">
</asp:button>
</form>
</body>
</html>
<%@ page language="C#" %>
<html>
<head id="Head1" runat="server">
<title>Button.PostBackUrl Example</title>
</head>
<body>
<form id="Form1" runat="server">
<h3>Button.PostBackUrl Example</h3>
Enter a value to post:
<asp:textbox id="TextBox1"
runat=Server>
</asp:textbox>
<br><br />
<asp:button id="Button1"
text="Post back to this page"
runat="Server">
</asp:button>
<br /><br />
<asp:button id="Button2"
text="Post value to another page"
postbackurl="Button.PostBackUrlPage2cs.aspx"
runat="Server">
</asp:button>
</form>
</body>
</html>
The following code example demonstrates how to use the Page.PreviousPage property to access a value that was posted from another page using the PostBackUrl property. This page gets the string that was posted from the previous page and displays it to the user. If you attempt to run this code example directly, you will get an error because the value of the text field will be a null reference (Nothing in Visual Basic). Instead, use this code to create a target page and place the file in the same directory as the code for the previous example. The name of the file must correspond to the value specified for the PostBackUrl property in the previous example. When you run the code for the previous example, this page will execute automatically when the cross page post occurs.
<%@ page language="VB" %>
<script runat="server">
Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs)
Dim text As String
' Get the value of TextBox1 from the page that posted
' to this page.
text = CType((PreviousPage.FindControl("TextBox1")), TextBox).Text
' Check for an empty string.
If Not (text = "") Then
PostedLabel.Text = "The string posted from the previous page is " _
& text & "."
Else
PostedLabel.Text = "An empty string was posted from the previous page."
End If
End Sub
</script>
<html>
<head id="Head1" runat="server">
<title>Button.PostBackUrl Target Page Example</title>
</head>
<body>
<form id="Form1" runat="server">
<h3>Button.PostBackUrl Target Page Example</h3>
<br />
<asp:label id="PostedLabel"
runat=Server>
</asp:label>
</form>
</body>
</html>
<%@ page language="C#" %>
<script runat="server">
void Page_Load (object sender, System.EventArgs e)
{
string text;
// Get the value of TextBox1 from the page that
// posted to this page.
text = ((TextBox)PreviousPage.FindControl("TextBox1")).Text;
// Check for an empty string.
if (text != "")
PostedLabel.Text = "The string posted from the previous page is "
+ text + ".";
else
PostedLabel.Text = "An empty string was posted from the previous page.";
}
</script>
<html>
<head id="Head1" runat="server">
<title>Button.PostBackUrl Target Page Example</title>
</head>
<body>
<form id="Form1" runat="server">
<h3>Button.PostBackUrl Target Page Example</h3>
<br />
<asp:label id="PostedLabel"
runat=Server>
</asp:label>
</form>
</body>
</html>