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Type::IsAutoLayout Property

Gets a value indicating whether the fields of the current type are laid out automatically by the common language runtime.

Namespace:  System
Assembly:  mscorlib (in mscorlib.dll)

public:
virtual property bool IsAutoLayout {
	bool get () sealed;
}

Property Value

Type: System::Boolean
true if the Attributes property of the current type includes TypeAttributes::AutoLayout; otherwise, false.

Implements

_Type::IsAutoLayout

This property is provided as a convenience. Alternatively, you can use the TypeAttributes::LayoutMask enumeration value to select the type layout attributes, and then test whether TypeAttributes::AutoLayout is set. The TypeAttributes::AutoLayout, TypeAttributes::ExplicitLayout, and TypeAttributes::SequentialLayout enumeration values indicate the way the fields of the type are laid out in memory.

For dynamic types, you can specify TypeAttributes::AutoLayout when you create the type. In code, apply the StructLayoutAttribute attribute with the LayoutKind::Auto enumeration value to the type, to let the runtime determine the appropriate way to lay out the class.

NoteNote

You cannot use the GetCustomAttributes method to determine whether the StructLayoutAttribute has been applied to a type.

If the current Type represents a constructed generic type, this property applies to the generic type definition from which the type was constructed. For example, if the current Type represents MyGenericType<int> (MyGenericType(Of Integer) in Visual Basic), the value of this property is determined by MyGenericType<T>.

If the current Type represents a type parameter in the definition of a generic type or generic method, this property always returns false.

The following example creates an instance of the type and displays the IsAutoLayout property.

#using <System.dll>

using namespace System;
using namespace System::Reflection;
using namespace System::ComponentModel;
using namespace System::Runtime::InteropServices;

// The MyDemoAttribute class is selected as AutoLayout.

[StructLayoutAttribute(LayoutKind::Auto)]
public ref class MyDemoAttribute{};

void MyAutoLayoutMethod( String^ typeName )
{
   try
   {

      // Create an instance of the Type class using the GetType method.
      Type^ myType = Type::GetType( typeName );

      // Get and display the IsAutoLayout property of the 
      // MyDemoAttribute instance.
      Console::WriteLine( "\nThe AutoLayout property for the MyDemoAttribute is {0}.", myType->IsAutoLayout );
   }
   catch ( Exception^ e ) 
   {
      Console::WriteLine( "\nAn exception occurred: {0}.", e->Message );
   }

}

int main()
{
   MyAutoLayoutMethod( "MyDemoAttribute" );
}

.NET Framework

Supported in: 4.6, 4.5, 4, 3.5, 3.0, 2.0, 1.1, 1.0

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

Supported in: Windows Phone 8.1

Supported in: Windows Phone Silverlight 8.1

Supported in: Windows Phone Silverlight 8

Windows Phone 8.1, Windows Phone 8, Windows 8.1, Windows Server 2012 R2, Windows 8, Windows Server 2012, Windows 7, Windows Vista SP2, Windows Server 2008 (Server Core Role not supported), Windows Server 2008 R2 (Server Core Role supported with SP1 or later; Itanium not supported)

The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

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