Updated: August 2008
Removes all trailing occurrences of a set of characters specified in an array from the current String object.
Namespace:
System
Assembly:
mscorlib (in mscorlib.dll)
Visual Basic (Declaration)
Public Function TrimEnd ( _
ParamArray trimChars As Char() _
) As String
Dim instance As String
Dim trimChars As Char()
Dim returnValue As String
returnValue = instance.TrimEnd(trimChars)
public string TrimEnd(
params char[] trimChars
)
public:
String^ TrimEnd(
... array<wchar_t>^ trimChars
)
public function TrimEnd(
... trimChars : char[]
) : String
Parameters
- trimChars
- Type: array<System..::.Char>[]()[]
An array of Unicode characters to remove or nullNothingnullptra null reference (Nothing in Visual Basic).
Return Value
Type:
System..::.StringThe string that remains after all occurrences of the characters in the trimChars parameter are removed from the end of the current String object. If trimChars is nullNothingnullptra null reference (Nothing in Visual Basic) or an empty array, white-space characters are removed instead.
The TrimEnd method removes from the current string all trailing characters that are in the trimChars parameter. The trim operation stops when a character that is not in trimChars is encountered. For example, if the current string is "123abc456xyz789" and trimChars contains the digits from '1' through '9', the TrimEnd method returns "123abc456xyz".
Note: |
|---|
This method does not modify the value of the current instance. Instead, it returns a new string in which all trailing white space characters found in the current instance are removed. |
For more information about which Unicode characters are categorized as white-space characters, see the Remarks section of the String..::.Trim()()() method overload.
The following example demonstrates how you can use the TrimEnd(array<Char>[]()[]) method overload to trim white space or punctuation marks from the end of a string.
Module TrimEnd
Public Sub Main()
Dim sentence As String = "The dog had a bone, a ball, and other toys."
Dim charsToTrim() As Char = {","c, "."c, " "c}
Dim words() As String = sentence.Split()
For Each word As String In words
Console.WriteLine(word.TrimEnd(charsToTrim))
Next
End Sub
End Module
' The example displays the following output:
' The
' dog
' had
' a
' bone
' a
' ball
' and
' other
' toys
using System;
public class TrimEnd
{
public static void Main()
{
string sentence = "The dog had a bone, a ball, and other toys.";
char[] charsToTrim = {',', '.', ' '};
string[] words = sentence.Split();
foreach (string word in words)
Console.WriteLine(word.TrimEnd(charsToTrim));
}
}
// The example displays the following output:
// The
// dog
// had
// a
// bone
// a
// ball
// and
// other
// toys
Windows 7, Windows Vista, Windows XP SP2, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP Starter Edition, Windows Server 2008 R2, Windows Server 2008, Windows Server 2003, Windows Server 2000 SP4, Windows Millennium Edition, Windows 98, Windows CE, Windows Mobile for Smartphone, Windows Mobile for Pocket PC, Xbox 360, Zune
The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
.NET Framework
Supported in: 3.5, 3.0, 2.0, 1.1, 1.0
.NET Compact Framework
Supported in: 3.5, 2.0, 1.0
XNA Framework
Supported in: 3.0, 2.0, 1.0
Reference
Date | History | Reason |
|---|
August 2008
| Replaced the example. |
Customer feedback.
|