Math.Exp Method
.NET Framework 3.5
Returns e raised to the specified power.
Assembly: mscorlib (in mscorlib.dll)
Parameters
- d
- Type: System.Double
A number specifying a power.
Return Value
Type: System.DoubleThe number e raised to the power d. If d equals NaN or PositiveInfinity, that value is returned. If d equals NegativeInfinity, 0 is returned.
The following example uses Exp to evaluate certain exponential and logarithmic identities for selected values.
// Example for the Math.Exp( double ) method. using System; class ExpDemo { public static void Main() { Console.WriteLine( "This example of Math.Exp( double ) " + "generates the following output.\n" ); Console.WriteLine( "Evaluate [e ^ ln(X) == ln(e ^ X) == X] " + "with selected values for X:" ); UseLnExp(0.1); UseLnExp(1.2); UseLnExp(4.9); UseLnExp(9.9); Console.WriteLine( "\nEvaluate these identities with " + "selected values for X and Y:" ); Console.WriteLine( " (e ^ X) * (e ^ Y) == e ^ (X + Y)" ); Console.WriteLine( " (e ^ X) ^ Y == e ^ (X * Y)" ); Console.WriteLine( " X ^ Y == e ^ (Y * ln(X))" ); UseTwoArgs(0.1, 1.2); UseTwoArgs(1.2, 4.9); UseTwoArgs(4.9, 9.9); } // Evaluate logarithmic/exponential identity with a given argument. static void UseLnExp(double arg) { // Evaluate e ^ ln(X) == ln(e ^ X) == X. Console.WriteLine( "\n Math.Exp(Math.Log({0})) == {1:E16}\n" + " Math.Log(Math.Exp({0})) == {2:E16}", arg, Math.Exp(Math.Log(arg)), Math.Log(Math.Exp(arg)) ); } // Evaluate exponential identities that are functions of two arguments. static void UseTwoArgs(double argX, double argY) { // Evaluate (e ^ X) * (e ^ Y) == e ^ (X + Y). Console.WriteLine( "\nMath.Exp({0}) * Math.Exp({1}) == {2:E16}" + "\n Math.Exp({0} + {1}) == {3:E16}", argX, argY, Math.Exp(argX) * Math.Exp(argY), Math.Exp(argX + argY) ); // Evaluate (e ^ X) ^ Y == e ^ (X * Y). Console.WriteLine( " Math.Pow(Math.Exp({0}), {1}) == {2:E16}" + "\n Math.Exp({0} * {1}) == {3:E16}", argX, argY, Math.Pow(Math.Exp(argX), argY), Math.Exp(argX * argY) ); // Evaluate X ^ Y == e ^ (Y * ln(X)). Console.WriteLine( " Math.Pow({0}, {1}) == {2:E16}" + "\nMath.Exp({1} * Math.Log({0})) == {3:E16}", argX, argY, Math.Pow(argX, argY), Math.Exp(argY * Math.Log(argX)) ); } } /* This example of Math.Exp( double ) generates the following output. Evaluate [e ^ ln(X) == ln(e ^ X) == X] with selected values for X: Math.Exp(Math.Log(0.1)) == 1.0000000000000001E-001 Math.Log(Math.Exp(0.1)) == 1.0000000000000008E-001 Math.Exp(Math.Log(1.2)) == 1.2000000000000000E+000 Math.Log(Math.Exp(1.2)) == 1.2000000000000000E+000 Math.Exp(Math.Log(4.9)) == 4.9000000000000012E+000 Math.Log(Math.Exp(4.9)) == 4.9000000000000004E+000 Math.Exp(Math.Log(9.9)) == 9.9000000000000004E+000 Math.Log(Math.Exp(9.9)) == 9.9000000000000004E+000 Evaluate these identities with selected values for X and Y: (e ^ X) * (e ^ Y) == e ^ (X + Y) (e ^ X) ^ Y == e ^ (X * Y) X ^ Y == e ^ (Y * ln(X)) Math.Exp(0.1) * Math.Exp(1.2) == 3.6692966676192444E+000 Math.Exp(0.1 + 1.2) == 3.6692966676192444E+000 Math.Pow(Math.Exp(0.1), 1.2) == 1.1274968515793757E+000 Math.Exp(0.1 * 1.2) == 1.1274968515793757E+000 Math.Pow(0.1, 1.2) == 6.3095734448019331E-002 Math.Exp(1.2 * Math.Log(0.1)) == 6.3095734448019344E-002 Math.Exp(1.2) * Math.Exp(4.9) == 4.4585777008251705E+002 Math.Exp(1.2 + 4.9) == 4.4585777008251716E+002 Math.Pow(Math.Exp(1.2), 4.9) == 3.5780924170885260E+002 Math.Exp(1.2 * 4.9) == 3.5780924170885277E+002 Math.Pow(1.2, 4.9) == 2.4433636334442981E+000 Math.Exp(4.9 * Math.Log(1.2)) == 2.4433636334442981E+000 Math.Exp(4.9) * Math.Exp(9.9) == 2.6764450551890982E+006 Math.Exp(4.9 + 9.9) == 2.6764450551891015E+006 Math.Pow(Math.Exp(4.9), 9.9) == 1.1684908531676833E+021 Math.Exp(4.9 * 9.9) == 1.1684908531676829E+021 Math.Pow(4.9, 9.9) == 6.8067718210957060E+006 Math.Exp(9.9 * Math.Log(4.9)) == 6.8067718210956985E+006 */
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