Path.GetFileName Method
Returns the file name and extension of the specified path string.
Assembly: mscorlib (in mscorlib.dll)
Parameters
- path
- Type: System.String
The path string from which to obtain the file name and extension.
Return Value
Type: System.StringThe characters after the last directory character in path. If the last character of path is a directory or volume separator character, this method returns String.Empty. If path is null, this method returns null.
| Exception | Condition |
|---|---|
| ArgumentException | path contains one or more of the invalid characters defined in GetInvalidPathChars. |
The returned value is null if the file path is null.
The separator characters used to determine the start of the file name are DirectorySeparatorChar and AltDirectorySeparatorChar.
For a list of common I/O tasks, see Common I/O Tasks.
The following code example demonstrates the behavior of the GetFileName method on a Windows-based desktop platform.
string fileName = @"C:\mydir\myfile.ext"; string path = @"C:\mydir\"; string result; result = Path.GetFileName(fileName); Console.WriteLine("GetFileName('{0}') returns '{1}'", fileName, result); result = Path.GetFileName(path); Console.WriteLine("GetFileName('{0}') returns '{1}'", path, result); // This code produces output similar to the following: // // GetFileName('C:\mydir\myfile.ext') returns 'myfile.ext' // GetFileName('C:\mydir\') returns ''
Windows 8, Windows Server 2012, Windows 7, Windows Vista SP2, Windows Server 2008 (Server Core Role not supported), Windows Server 2008 R2 (Server Core Role supported with SP1 or later; Itanium not supported)
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
