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DateTime.Subtract Method

Subtracts the specified time or duration from this instance.

Overload List

Subtracts the specified date and time from this instance.

Supported by the .NET Compact Framework.

[Visual Basic] Overloads Public Function Subtract(DateTime) As TimeSpan
[C#] public TimeSpan Subtract(DateTime);
[C++] public: TimeSpan Subtract(DateTime);
[JScript] public function Subtract(DateTime) : TimeSpan;

Subtracts the specified duration from this instance.

Supported by the .NET Compact Framework.

[Visual Basic] Overloads Public Function Subtract(TimeSpan) As DateTime
[C#] public DateTime Subtract(TimeSpan);
[C++] public: DateTime Subtract(TimeSpan);
[JScript] public function Subtract(TimeSpan) : DateTime;

Example

[Visual Basic, C#, C++] The following sample demonstrates the Subtract method and operator.

[Visual Basic, C#, C++] Note   This example shows how to use one of the overloaded versions of Subtract. For other examples that might be available, see the individual overload topics.
[Visual Basic] 
Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)

Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)

Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)

Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)

Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)

[C#] 
System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);

// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);

// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);

// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;

[C++] 
System::DateTime date1 = System::DateTime(1996, 6, 3, 22, 15, 0);
System::DateTime date2 = System::DateTime(1996, 12, 6, 13, 2, 0);
System::DateTime date3 = System::DateTime(1996, 10, 12, 8, 42, 0);

// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract(date1);

// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract(diff1);

// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;

// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;

[JScript] No example is available for JScript. To view a Visual Basic, C#, or C++ example, click the Language Filter button Language Filter in the upper-left corner of the page.

See Also

DateTime Structure | DateTime Members | System Namespace

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