Updated: March 2012
Returns the number of days in the specified month and year.
Assembly: mscorlib (in mscorlib.dll)
Public Shared Function DaysInMonth ( _ year As Integer, _ month As Integer _ ) As Integer
public static int DaysInMonth( int year, int month )
public: static int DaysInMonth( int year, int month )
static member DaysInMonth : year:int * month:int -> int
Parameters
- year
- Type: System.Int32
The year.
- month
- Type: System.Int32
The month (a number ranging from 1 to 12).
Return Value
Type: System.Int32The number of days in month for the specified year.
For example, if month equals 2 for February, the return value is 28 or 29 depending upon whether year is a leap year.
| Exception | Condition |
|---|---|
| ArgumentOutOfRangeException |
month is less than 1 or greater than 12. -or- year is less than 1 or greater than 9999. |
The DaysInMonth method always interprets month and year as the month and year of the Gregorian calendar even if the Gregorian calendar is not the current culture's current calendar. To get the number of days in a specified month of a particular calendar, call that calendar's GetDaysInMonth method.
The following example demonstrates the DaysInMonth method.
Const July As Integer = 7 Const Feb As Integer = 2 ' daysInJuly gets 31. Dim daysInJuly As Integer = System.DateTime.DaysInMonth(2001, July) ' daysInFeb gets 28 because the year 1998 was not a leap year. Dim daysInFeb As Integer = System.DateTime.DaysInMonth(1998, Feb) ' daysInFebLeap gets 29 because the year 1996 was a leap year. Dim daysInFebLeap As Integer = System.DateTime.DaysInMonth(1996, Feb)
const int July = 7; const int Feb = 2; // daysInJuly gets 31. int daysInJuly = System.DateTime.DaysInMonth(2001, July); // daysInFeb gets 28 because the year 1998 was not a leap year. int daysInFeb = System.DateTime.DaysInMonth(1998, Feb); // daysInFebLeap gets 29 because the year 1996 was a leap year. int daysInFebLeap = System.DateTime.DaysInMonth(1996, Feb);
const int July = 7; const int Feb = 2; // daysInJuly gets 31. int daysInJuly = System::DateTime::DaysInMonth( 2001, July ); // daysInFeb gets 28 because the year 1998 was not a leap year. int daysInFeb = System::DateTime::DaysInMonth( 1998, Feb ); // daysInFebLeap gets 29 because the year 1996 was a leap year. int daysInFebLeap = System::DateTime::DaysInMonth( 1996, Feb );
.NET Framework
Supported in: 4, 3.5, 3.0, 2.0, 1.1, 1.0.NET Framework Client Profile
Supported in: 4, 3.5 SP1Portable Class Library
Supported in: Portable Class LibraryWindows 7, Windows Vista SP1 or later, Windows XP SP3, Windows XP SP2 x64 Edition, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2
The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
Reference
|
Date |
History |
Reason |
|---|---|---|
|
March 2012 |
Added the Remarks section. |
Customer feedback. |
DateTime uses proleptic Gregorian calendar, i.e. DateTime.DaysInMonth(1000,2) returns 28. (Year 1000 is not a leap year according to Gregorian rules, but is a leap year according to Julian calendar.)
Days in a Month in the Julian Calendar
To get the number of days in a month in the Julian Calendar, you can call the JulianCalendar.GetDaysInMonth method. This shows that February 1000 has 29 days:
using System;
using System.Globalization;
public class Example
{
public static void Main()
{
JulianCalendar cal = new JulianCalendar();
Console.WriteLine(cal.GetDaysInMonth(1000, 2)); // Displays 29
}
}
In general, for any calendar, you can get the number of days in a month by calling that calendar's GetDaysInMonth method.
--Ron Petrusha
Common Language Runtime User Education
Microsoft Corporation