DateTime.Date Property

The value of the Kind property of the returned DateTime value is the same as that of the current instance.

Because the DateTime type represents both dates and times in a single type, it is important to avoid misinterpreting a date returned by the Date property as a date and time. For more information, see "Saving and Restoring DateTime Values" in the DateTime topic.

The following example uses the Date property to extract the date component of a DateTime value with its time component set to zero (or 0:00:00, or midnight). It also illustrates that, depending on the format string used when displaying the DateTime value, the time component can continue to appear in formatted output.

DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
Console.WriteLine(date1.ToString());

// Get date-only portion of date, without its time.
DateTime dateOnly = date1.Date;
// Display date using short date string.
Console.WriteLine(dateOnly.ToString("d"));
// Display date using 24-hour clock.
Console.WriteLine(dateOnly.ToString("g"));
Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));   
// The example displays the following output to the console: 
//       6/1/2008 7:47:00 AM 
//       6/1/2008 
//       6/1/2008 12:00 AM 
//       06/01/2008 00:00

.NET Framework

.NET Framework Client Profile

Portable Class Library

.NET for Windows Store apps

Windows 8, Windows Server 2012, Windows 7, Windows Vista SP2, Windows Server 2008 (Server Core Role not supported), Windows Server 2008 R2 (Server Core Role supported with SP1 or later; Itanium not supported)

The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

Reference