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DateTime.AddDays Method

Adds the specified number of days to the value of this instance.

Namespace: System
Assembly: mscorlib (in mscorlib.dll)

public DateTime AddDays (
	double value
)
public DateTime AddDays (
	double value
)
public function AddDays (
	value : double
) : DateTime

Parameters

value

A number of whole and fractional days. The value parameter can be negative or positive.

Return Value

A DateTime whose value is the sum of the date and time represented by this instance and the number of days represented by value.
Exception typeCondition

ArgumentOutOfRangeException

The resulting DateTime is less than MinValue or greater than MaxValue.

This method does not change the value of this DateTime. Instead, a new DateTime is returned whose value is the result of this operation.

The fractional part of value is the fractional part of a day. For example, 4.5 is equivalent to 4 days, 12 hours, 0 minutes, 0 seconds, 0 milliseconds, and 0 ticks.

The value parameter is rounded to the nearest millisecond.

The following code example demonstrates the AddDays method.

// Calculate what day of the week is 36 days from this instant.
System.DateTime today = System.DateTime.Now;
System.DateTime answer = today.AddDays(36);
System.Console.WriteLine("{0:dddd}", answer);

// Calculate what day of the week is 36 days from this instant.
System.DateTime today = System.DateTime.get_Now();
System.DateTime answer = today.AddDays(36);
System.Console.WriteLine("{0:dddd}", answer);

Windows 98, Windows 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

The .NET Framework does not support all versions of every platform. For a list of the supported versions, see System Requirements.

.NET Framework

Supported in: 2.0, 1.1, 1.0

.NET Compact Framework

Supported in: 2.0, 1.0
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