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Job.Start Method

Runs the referenced job.

Namespace:  Microsoft.SqlServer.Management.Smo.Agent
Assembly:  Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)

public void Start()

The following code example creates a job and starts it.

C#

Server srv = new Server("(local)");
Job jb = new Job(srv.JobServer, "Test Job");
jb.Create();
JobStep jbstp = new JobStep(jb, "Test Job Step");
jbstp.OnSuccessAction = StepCompletionAction.QuitWithSuccess;
jbstp.OnFailAction = StepCompletionAction.QuitWithFailure;
jbstp.Create();
jb.ApplyToTargetServer(srv.Name);
jb.IsEnabled = true;
jb.Start();

PowerShell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$jb = new-object Microsoft.SqlServer.Management.Smo.Agent.Job($srv.JobServer, "Testrrt Job")
$jb.Create()
$jbstp = new-object Microsoft.SqlServer.Management.Smo.Agent.JobStep($jb, "Test Job Step")
$jbstp.OnSuccessAction = [Microsoft.SqlServer.Management.Smo.Agent.StepCompletionAction]::QuitWithSuccess
$jbstp.OnFailAction = [Microsoft.SqlServer.Management.Smo.Agent.StepCompletionAction]::QuitWithFailure
$jbstp.Create()
$jb.ApplyToTargetServer($srv.Name)
$jb.IsEnabled = $TRUE
$jb.Start()

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