How to: Deserialize an Object
When you deserialize an object, the transport format determines whether you will create a stream or file object. After the transport format is determined, you can call theor methods, as required.
To deserialize an object
Construct ausing the type of the object to deserialize.
Call the Deserialize method to produce a replica of the object. When deserializing, you must cast the returned object to the type of the original, as shown in the following example, which deserializes the object into a file (although it could also be deserialized into a stream).
Dim myObject As MySerializableClass ' Construct an instance of the XmlSerializer with the type ' of object that is being deserialized. Dim mySerializer As XmlSerializer = New XmlSerializer(GetType(MySerializableClass)) ' To read the file, create a FileStream. Dim myFileStream As FileStream = _ New FileStream("myFileName.xml", FileMode.Open) ' Call the Deserialize method and cast to the object type. myObject = CType( _ mySerializer.Deserialize(myFileStream), MySerializableClass)
MySerializableClass myObject; // Construct an instance of the XmlSerializer with the type // of object that is being deserialized. XmlSerializer mySerializer = new XmlSerializer(typeof(MySerializableClass)); // To read the file, create a FileStream. FileStream myFileStream = new FileStream("myFileName.xml", FileMode.Open); // Call the Deserialize method and cast to the object type. myObject = (MySerializableClass) mySerializer.Deserialize(myFileStream)