/out (Set Output File Name) (C# Compiler Options)
The /out option specifies the name of the output file.
/out:filename
On the command line, it is possible to specify multiple output files for your compilation. The compiler expects to find one or more source code files following the /out option. Then, all source code files will be compiled into the output file specified by that /out option.
Specify the full name and extension of the file you want to create.
If you do not specify the name of the output file:
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An .exe will take its name from the source code file that contains the Main method.
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A .dll or .netmodule will take its name from the first source code file.
A source code file used to compile one output file cannot be used in the same compilation for the compilation of another output file.
When producing multiple output files in a command-line compilation, keep in mind that only one of the output files can be an assembly and that only the first output file specified (implicitly or explicitly with /out) can be the assembly.
Any modules produced as part of a compilation become files associated with any assembly also produced in the compilation. Use ildasm.exe to view the assembly manifest to see the associated files.
The /out compiler option is required in order for an exe to be the target of a friend assembly. For more information see Friend Assemblies (C# Programming Guide).
To set this compiler option in the Visual Studio development environment
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Open the project's Properties page. For details, see How to: Set Project Properties (C#, J#).
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Click the Application property page.
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Modify the Assembly name property.
To set this compiler option programmatically: the OutputFileName is a read-only property, which is determined by a combination of the project type (exe, library, and so forth) and the assembly name. Modifying one or both of these properties will be necessary to set the output file name.
