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STWithin (geometry Data Type)

Returns 1 if a geometry instance is completely within another geometry instance; otherwise, returns 0.

Applies to: SQL Server (SQL Server 2008 through current version), Azure SQL Database.

.STWithin ( other_geometry )

other_geometry

Is another geometry instance to compare against the instance on which STWithin() is invoked.

SQL Server return type: bit

CLR return type: SqlBoolean

This method always returns null if the spatial reference IDs (SRIDs) of the geometry instances do not match.

The following example uses STWithin() to test two geometry instances to see if the first instance is completely within the second instance.

DECLARE @g geometry;
DECLARE @h geometry;
SET @g = geometry::STGeomFromText('POLYGON((0 0, 2 0, 2 2, 0 2, 0 0))', 0);
SET @h = geometry::STGeomFromText('POLYGON((1 1, 3 1, 3 3, 1 3, 1 1))', 0);
SELECT @g.STWithin(@h);

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