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Enumerable.Min(Of TSource, TResult) Method (IEnumerable(Of TSource), Func(Of TSource, TResult))

Invokes a transform function on each element of a generic sequence and returns the minimum resulting value.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)
'Declaration
<ExtensionAttribute> _
Public Shared Function Min(Of TSource, TResult) ( _
	source As IEnumerable(Of TSource), _
	selector As Func(Of TSource, TResult) _
) As TResult

Type Parameters

TSource

The type of the elements of source.

TResult

The type of the value returned by selector.

Parameters

source
Type: System.Collections.Generic.IEnumerable(Of TSource)
A sequence of values to determine the minimum value of.
selector
Type: System.Func(Of TSource, TResult)
A transform function to apply to each element.

Return Value

Type: TResult
The minimum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable(Of TSource). When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).
ExceptionCondition
ArgumentNullException

source or selector is Nothing.

If type TResult implements IComparable(Of T), this method uses that implementation to compare values. Otherwise, if type TResult implements IComparable, that implementation is used to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

The following code example demonstrates how to use Min(Of TSource)(IEnumerable(Of TSource), Func(Of TSource, Int32)) to determine the minimum value in a sequence of projected values.

NoteNote

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, change the body of the selector function.


    Structure Pet
        Public Name As String
        Public Age As Integer
    End Structure

    Sub MinEx4()
        ' Create an array of Pet objects.
        Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8}, _
                             New Pet With {.Name = "Boots", .Age = 4}, _
                             New Pet With {.Name = "Whiskers", .Age = 1}}

        ' Find the youngest pet by passing a 
        ' lambda expression to the Min() method.
        Dim min As Integer = pets.Min(Function(pet) pet.Age)

        ' Display the result.
        MsgBox("The youngest pet is age " & min)
    End Sub

    ' This code produces the following output:
    '
    ' The youngest pet is age 1



.NET Framework

Supported in: 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

Portable Class Library

Supported in: Portable Class Library

Windows 7, Windows Vista SP1 or later, Windows XP SP3, Windows Server 2008 (Server Core not supported), Windows Server 2008 R2 (Server Core supported with SP1 or later), Windows Server 2003 SP2

The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
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