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Enumerable.Min Method (IEnumerable<Single>)

Returns the minimum value in a sequence of Single values.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

public static float Min(
	this IEnumerable<float> source
)

Parameters

source
Type: System.Collections.Generic.IEnumerable<Single>
A sequence of Single values to determine the minimum value of.

Return Value

Type: System.Single
The minimum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Single>. When you use instance method syntax to call this method, omit the first parameter.

ExceptionCondition
ArgumentNullException

source is null.

InvalidOperationException

source contains no elements.

The Min(IEnumerable<Single>) method uses the Single implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

NoteNote:

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.


      double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

      double min = doubles.Min();

      outputBlock.Text += String.Format("The smallest number is {0}.", min) + "\n";

      /*
       This code produces the following output:

       The smallest number is -2E+103.
      */



Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

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