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Enumerable.Max Method (IEnumerable<Int64>)

Returns the maximum value in a sequence of Int64 values.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

public static long Max(
	this IEnumerable<long> source
)

Parameters

source
Type: System.Collections.Generic.IEnumerable<Int64>

A sequence of Int64 values to determine the maximum value of.

Return Value

Type: System.Int64
The maximum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Int64>. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

ExceptionCondition
ArgumentNullException

source is null.

InvalidOperationException

source contains no elements.

The Max(IEnumerable<Int64>) method uses the Int64 implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

long max = longs.Max();

Console.WriteLine("The largest number is {0}.", max);

/*
 This code produces the following output:

 The largest number is 4294967296.
*/

Windows 7, Windows Vista, Windows XP SP2, Windows Server 2008 R2, Windows Server 2008, Windows Server 2003, Windows CE, Windows Mobile for Smartphone, Windows Mobile for Pocket PC, Xbox 360, Zune

The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.

.NET Framework

Supported in: 3.5

.NET Compact Framework

Supported in: 3.5

XNA Framework

Supported in: 3.0

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